Practice question
Question
What is the mole fraction of benzene (molar mass = 78 g/mol) in a solution containing 39 g of benzene and 92 g of toluene (molar mass = 92 g/mol)?
Explanation
Moles of benzene = (39/78) = 0.5 mol . Moles of toluene = (92/92) = 1 mol . Total moles = 0.5 + 1 = 1.5 . Mole fraction = (0.5/1.5) ≈ 0.333 .
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