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Laws of Chemical Combination - Conservation Mass Definite Multiple

Introduces the fundamental laws governing chemical reactions, including the conservation of mass and the laws of definite and multiple proportions.

29 questions

How many grams of MgCl₂ are produced when 9.5 g of Mg(OH)₂ reacts with excess HCl? (Molar masses: Mg(OH)₂ = 58 g/mol, Mg

Reaction: Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O. Moles of Mg(OH)₂ ≈ 0.1638 mol. 1 mol Mg(OH)₂ produces 1 mol MgCl₂; mass ≈ 15.56 g.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What is the mass of CaSO₄ produced when 13.6 g of Ca(OH)₂ reacts with excess H₂SO₄? (Molar masses: Ca(OH)₂ = 74 g/mol, C

Reaction: Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O. Moles of Ca(OH)₂ ≈ 0.1838 mol. 1 mol Ca(OH)₂ produces 1 mol CaSO₄; mass ≈ 25 g.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What volume of O₂ at STP is required to burn 11 g of C₂H₆ completely to CO₂ and H₂O? (Molar mass: C₂H₆ = 30 g/mol)

Reaction: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O. Moles of C₂H₆ ≈ 0.3667 mol. 2 mol need 7 mol O₂; 0.3667 mol need ≈ 1.2833 mol. Volume = 1.2833 × 22.4 ≈ 28.75 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What volume of N₂ at STP is required to react with 6 g of H₂ to produce NH₃ with 60% yield? (Molar mass: H₂ = 2 g/mol)

Reaction: N₂ + 3H₂ → 2NH₃. Moles of H₂ = 3 mol. 3 mol H₂ need 1 mol N₂; actual N₂ = 1 / 0.6 ≈ 1.67 mol. Volume = 1.67 × 22.4 ≈ 37.41 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

How many grams of H₂SO₄ are required to neutralize 8 g of NaOH completely? (Molar masses: H₂SO₄ = 98 g/mol, NaOH = 40 g/

Reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Moles of NaOH = 8/40 = 0.2 mol. 2 mol NaOH need 1 mol H₂SO₄; 0.2 mol needs 0.1 mol. Mass = 0.1 × 98 = 9.8 g.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What volume of CO₂ at STP is produced when 11.2 g of C₅H₁₂ is burned completely? (Molar mass: C₅H₁₂ = 72 g/mol)

Reaction: C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O. Moles of C₅H₁₂ = 11.2/72 ≈ 0.1556 mol. 1 mol produces 5 mol CO₂; 0.1556 mol produces 0.7778 mol. Volume = 0.7778 × 22.4 ≈ 17.42 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple