Practice question
Question
A 0.15 M KOH solution is diluted by adding 150 mL of water to 50 mL of the original solution. What is the final molarity?
Explanation
M₁V₁ = M₂V₂. 0.15 × 50 = M₂ × (50 + 150). M₂ = (0.15 × 50)/200 = 0.0375 M.
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