Latest questions in this category.
Close boiling points (4°C difference) require fractional distillation for effective separation.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Close boiling points (5°C difference) require fractional distillation for large-scale separation.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
In HC≡C-CH=CH₂, the triple bond (C≡C) has 2 π bonds, and the double bond (C=C) has 1 π bond. Total = 3.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Simple distillation is effective for separating liquids with boiling point differences > 25°C.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Differential extraction uses two immiscible solvents (e.g., water and ether) to separate compounds based on their solubility differences.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Sublimation separates solids that transition directly to the gas phase upon heating (e.g., naphthalene) from non-sublimable impurities.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
In CH₂=CH-CH=CH₂ (buta-1,3-diene), each double bond has 1 π bond. There are 2 double bonds, so total π bonds = 2.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Sublimation would separate the sublimable solid effectively. Crystallization, requiring a solvent, is less suitable as it’s designed for soluble impurities, not thermal properties.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Sublimation separates the solid that sublimes at 60°C from the one that melts at 120°C, exploiting the phase change difference.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
In CH₃C≡CH (propyne), there are 6 σ bonds (3 C-H, 1 C-C, 2 from C≡C) and 2 π bonds (from C≡C). Total = 6 + 2 = 8.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Simple distillation is suitable for separating liquids with boiling point differences greater than 25–30°C.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
Crystallization removes soluble impurities by dissolving the solid in a solvent and allowing it to recrystallize.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Purification Methods - Crystallization Distillation Chromatography
