Practice questions on conductance, conductivity, molar conductivity, and Kohlrausch’s law with step-by-step solutions for competitive and board exams.
Lambdam° = λ°Ca²⁺ + 2 λ°Cl⁻ = 119 + 2 × 76.3 = 271.6 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Moles of Cu = (0.635/63.5) = 0.01 mol . Charge = 0.01 × 2 × 96500 = 1930 C . t = (Q/I) = (1930/0.5) = 3860 s .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam° = λ°Ba²⁺ + 2λ°Cl⁻ . 280 = 127 + 2λ°Cl⁻ , 2λ°Cl⁻ = 153 , λ°Cl⁻ = 76.5 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam° = λ°K⁺ + λ°Br⁻ . 151.8 = 73.5 + λ°Br⁻ , λ°Br⁻ = 78.3 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
kappa = (cell constant/R) = (0.6/200) = 0.003 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.003 × 1000/0.03) = 100 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.00195 × 1000/0.015) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = sqrt(Ka/c) = sqrt(1.78 × 10⁻⁵/0.001) = 0.133 . α = (Lambdam/Lambdam°) , 0.133 = (48.15/Lambdam°) , Lambdam° = 390.5 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam° = λ°Rb⁺ + λ°Cl⁻ . 152.7 = 77.8 + λ°Cl⁻ , λ°Cl⁻ = 74.9 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
ClO₄⁻ + 8H⁺ + 8e⁻ → Cl⁻ + 4H₂O . 8 electrons per mole.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
kappa = (cell constant/R) = (0.5/200) = 0.0025 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.0025 × 1000/0.02) = 125 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam° = λ°Cs⁺ + λ°Cl⁻ . 153.3 = 77.0 + λ°Cl⁻ , λ°Cl⁻ = 76.3 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
