Practice question
Question
What is the limiting molar conductivity of CaCl₂ in water at 298 K, given λ°Ca²⁺ = 119 S cm² mol⁻¹ , λ°Cl⁻ = 76.3 S cm² mol⁻¹ ?
Explanation
Lambdam° = λ°Ca²⁺ + 2 λ°Cl⁻ = 119 + 2 × 76.3 = 271.6 S cm² mol⁻¹ .
We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policyMCQ
Question
Guides and insights connected to this topic
Explore the key physical and chemical traits of metals and non‑metals, including lustre, hardness, malleability, ductility, conductivity and corrosion.
Explore how cells form tissues in plants and animals, covering meristematic, epithelial, connective and muscular types, and why their structures differ.
Learn how mixtures are classified as homogeneous or heterogeneous and discover basic separation methods such as filtration, evaporation and distillation.
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.