Explores the evolution of atomic models from Thomson’s plum pudding model to Rutherford’s nuclear model and Bohr’s quantized orbits. Includes practice questions for clarity.
n=4. For C⁵⁺ (Z=6), v₄ = 3.285×10⁶ m s⁻¹. KE ≈ 4.91×10⁻¹⁸ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
λ = h/(mv) ≈ 1.33×10⁻⁹ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
E ≈ 4.14 eV. KE = 1.14 eV. Vₛ = 1.14 V.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
Δv ≥ h/(4π m Δx) ≈ 6.3×10² m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
Δp ≥ h/(4π Δx) = 2.64×10⁻²⁵ kg m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
For Li²⁺ (Z=3), ΔE = 25.704 eV. λ ≈ 48.34 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
v₃ = v₁/3 = 7.3×10⁵ m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
W₀ = hc/λ₀ = 3.9756×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
λ = h/(mv) = 3.64×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
r₂ = 4 × r₁ = 2.116×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
KE₂(He⁺)/KE₃(H) ≈ 9.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
λ = h/(mv) ≈ 3.966×10⁻¹³ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Atomic Models - Thomson Rutherford and Bohr Model
