Latest questions in this category.
Lambdam = (kappa × 1000/c) = (0.00325 × 1000/0.025) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Lambdam = (kappa × 1000/c) = (0.00325 × 1000/0.025) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Charge = 2 × 5 × 3600 = 36000 C . Cathode: PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ → PbSO₄ + 2H₂O . 1 mol PbO₂ requires 2F. Faradays = (36000/96500) = 0.373 F , Moles = (0.373/2) = 0.1865 mol , Mass = 0.1865 × 239 = 44.57 g .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Charge = 2 × 5 × 3600 = 36000 C . Cathode: PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ → PbSO₄ + 2H₂O . 1 mol PbO₂ requires 2F. Faradays = (36000/96500) = 0.373 F , Moles = (0.373/2) = 0.1865 mol , Mass = 0.1865 × 239 = 44.57 g .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
The anode in a lead storage battery is lead (Pb).
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
MnO₂ + H⁺ + e⁻ → MnO(OH) . Moles = (0.435/87) = 0.005 mol , Charge = 0.005 × 96500 = 482.5 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
MnO₂ + H⁺ + e⁻ → MnO(OH) . Moles = (0.435/87) = 0.005 mol , Charge = 0.005 × 96500 = 482.5 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Charging reverses discharge: Anode: PbSO₄ + 2H₂O → PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Charging reverses discharge: Anode: PbSO₄ + 2H₂O → PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Al³⁺ + 3e⁻ → Al . 1 mol Al (27 g) requires 3F. Moles = (5.4/27) = 0.2 mol , Charge = 0.2 × 3 × 96500 = 57900 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Al³⁺ + 3e⁻ → Al . 1 mol Al (27 g) requires 3F. Moles = (5.4/27) = 0.2 mol , Charge = 0.2 × 3 × 96500 = 57900 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O . Moles O₂ = (0.56/22.4) = 0.025 mol , Moles H₂O = 0.025 × 2 = 0.05 mol . Mass = 0.05 × 18 = 0.9 g .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
