NEET MOCK TEST

ZOOLOGY

Why do echinoderms exhibit bilateral symmetry in their larval stage but radial symmetry as adults?

Larval Stage: Bilateral symmetry enables free-swimming larvae to balance and move efficiently in open water. Adult Stage: Adult echinoderms live on the seafloor (benthic zone). Pentaradial symmetry allows them to feed and detect surroundings equally from all directions.

Ref: NCERT Biology Textbook - Latest Edition for Academic Session 2026-27 (Zoology section, Rationalized Textbook for Class XI and XII), Chapter: Biology - Zoology portion (Latest NCERT Textbooks for Academic Session 2026-27 - Rationalized Edition for Class XI and XII), Topic: Structural organization, physiology, human health and related concepts as per latest syllabus.

View Details

ZOOLOGY

Which of the following statements about frog locomotion is correct?

Hindlimbs: Muscular, elongated, and webbed with five digits. They propel the frog forward during leaping on land and paddling in water. Forelimbs: Short and unwebbed with four digits, designed to support the body and absorb landing impact.

Ref: NCERT Biology Textbook for Class XI and XII (Zoology section), Chapter: Structural Organisation in Animals and Frog, Topic: Tissues, skeletal and organ systems.

View Details

BOTANY

What is the probability of a son inheriting an X-linked recessive disorder if his mother is a carrier?

A son has a 50% chance of inheriting an X-linked recessive disorder from a carrier mother, as he receives one X chromosome from his mother. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Biology Textbook for Class XI and XII (Botany section), Chapter: Biology - Botany portion covering relevant concept.

View Details

CHEMISTRY

What is the number of unpaired electrons in [Cr(Hâ‚‚O)6]^{3+ ?

Given: What is the number of unpaired electrons in [Cr(H₂O)6]^{3+ ? These values define the system as per NCERT data. Formula: Cr³⁺ ( d³ ) with H₂O in an octahedral field has 3 unpaired electrons ( t_{2g³ ), as it’s a d³ system.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

View Details

CHEMISTRY

How many optical isomers are possible for [Cr(Câ‚‚Oâ‚„)3]^{3- ?

[Cr(Câ‚‚Oâ‚„)3]^{3- is octahedral with three bidentate oxalate ligands, lacking symmetry, and forms two optical isomers (d and l enantiomers). This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

What is the magnetic moment (in BM) of [Ni(NH₃)6]^{2+ ?

Given: What is the magnetic moment (in BM) of [Ni(NH₃)6]^{2+ ? These values define the system as per NCERT data. Formula: Magnetic moment = sqrt2(2+2) = sqrt8 approx 2.83 BM.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Ni²⁺ ( d⁸ ) with NH₃ (moderate field) in an octahedral field is high spin ( t_{2g⁶ e_g² ), with 2 unpaired electrons. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

A gaseous reaction follows Rate = k p_A² . If k = 0.1 atm^{-1 s^{-1 and p_A = 0.4 atm, what is the rate in atm s^{-1 ?

Given: A gaseous reaction follows Rate = k p_A² . If k = 0.1 atm^{-1 s^{-1 and p_A = 0.4 atm, what is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A² = 0.1 × (0.4)² = 0.1 × 0.16 = 0.016 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

The initial rate of a reaction is 2.0 × 10⁻³ mol L^{-1 s^{-1 when [A] = 0.5 M and [B] = 0.2 M. If the rate law is Ra

Given: The initial rate of a reaction is 2.0 × 10⁻³ mol L^{-1 s^{-1 when [A] = 0.5 M and [B] = 0.2 M. If the rate law is Rate = k[A][B], what is k in L mol^{-1 s^{-1 ? These values define the system as per NCERT data. Formula: k = fracRate[A][B] = frac2.0 × 10⁻³⁰.5 × 0.2 = 0.02 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

What is the mole fraction of NaCl in a solution containing 5.85 g of NaCl and 90 g of water? (Molar masses: NaCl = 58.5

Given: What is the mole fraction of NaCl in a solution containing 5.85 g of NaCl and 90 g of water? (Molar masses: NaCl = 58.5 g/mol, H₂O = 18 g/mol) These values define the system as per NCERT data. Formula: Moles of NaCl = 5.85 / 58.5 = 0.1 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Moles of H₂O = 90 / 18 = 5 mol. Total moles = 0.1 + 5 = 5.1. Mole fraction = 0.1 / 5.1 ≈ 0.0196. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

View Details

CHEMISTRY

For Nâ‚‚(g) + Oâ‚‚(g) 2NO(g), K_c = 0.02 at 1500 K. What is K_c for NO(g) 1/2 Nâ‚‚(g) + 1/2 Oâ‚‚(g) ?

Given: For N₂(g) + O₂(g) 2NO(g), K_c = 0.02 at 1500 K. What is K_c for NO(g) 1/2 N₂(g) + 1/2 O₂(g) ? These values define the system as per NCERT data. Formula: For the reverse halved reaction, K_c' = frac1sqrtK_c = frac1sqrt0.02 approx 7.07 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

A gaseous reaction follows Rate = k p_A² with k = 0.2 atm^{-1 s^{-1 and p_A = 0.5 atm . What is the rate in atm s^{-1 ?

Given: A gaseous reaction follows Rate = k p_A² with k = 0.2 atm^{-1 s^{-1 and p_A = 0.5 atm . What is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A² = 0.2 × (0.5)² = 0.2 × 0.25 = 0.05 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

View Details

CHEMISTRY

A solution contains 5 g of glucose dissolved in 95 g of water. What is the mass percentage of glucose?

Given: A solution contains 5 g of glucose dissolved in 95 g of water. What is the mass percentage of glucose? These values define the system as per NCERT data. Formula: Total mass = 5 + 95 = 100 g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass % = (5 / 100) × 100 = 5%. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

View Details