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CHEMISTRY

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45 questions

A compound has an empirical formula CHâ‚‚ and a molar mass of 70 g/mol. What is its molecular formula? (Atomic masses: C

Given: A compound has an empirical formula CH₂ and a molar mass of 70 g/mol. What is its molecular formula? (Atomic masses: C = 12, H = 1) These values define the system as per NCERT data. Formula: Empirical mass = 12 + (2 × 1) = 14 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: n = 70 / 14 = 5. Molecular formula = C₅H₁₀. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

What is the product when CH₃CH₂NH₂ reacts with CH₃CH₂COCH₃ followed by H₂/Ni ?

Ethanamine reacts with butan-2-one ( CH₃CH₂COCH₃ ) to form an imine, reduced by H₂/Ni to CH₃CH₂NHCH(CH₃)CH₂CH₃ (N-(butan-2-yl)ethanamine). This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the correct IUPAC name of glycerol?

Glycerol is a trihydroxy compound and its IUPAC name is propane-1, 2, 3-triol. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

The product formed when KMnOâ‚„ oxidizes NOâ‚‚^- in acidic medium is:

5NO₂^- + 2MnO₄^- + 6H^+ -> 2Mn^{2+ + 5NO₃^- + 3H₂O . Nitrite ( NO₂^- ) is oxidized to nitrate ( NO₃^- ). This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Calculate the freezing point depression of a solution made by dissolving 6 g of urea ( NHâ‚‚CONHâ‚‚ ) in 200 g of water.

Given: Calculate the freezing point depression of a solution made by dissolving 6 g of urea ( NH₂CONH₂ ) in 200 g of water. ( K_f = 1.86 K kg/mol, Molar mass of urea = 60 g/mol ) These values define the system as per NCERT data. Formula: Moles of urea = 6/60 = 0.1 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Molality = 0.1/0.2 = 0.5 mol/kg . Δ T_f = 1.86 × 0.5 = 0.93 K . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

What happens when propyne is treated with ammoniacal silver nitrate solution?

Terminal alkynes react with ammoniacal silver nitrate to form a white precipitate of silver acetylide. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

Which of the following elements is a chalcogen?

Chalcogens are Group 16 elements. Oxygen (O) belongs to this group, unlike F (Group 17), Na (Group 1), or Si (Group 14). This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.