NEET Mock Test 4 is a full practice attempt covering Physics, Chemistry and Biology questions in one sitting. Use it later in your preparation to check how your accuracy and pacing have changed, and review the answers to see which topics still need attention.
Hindlimbs: Muscular, elongated, and webbed with five digits. They propel the frog forward during leaping on land and paddling in water. Forelimbs: Short and unwebbed with four digits, designed to support the body and absorb landing impact.
Ref: NCERT Biology Textbook for Class XI and XII (Zoology section), Chapter: Structural Organisation in Animals and Frog, Topic: Tissues, skeletal and organ systems.
Given: What is the degree of dissociation of 0.01 M acetic acid if its molar conductivity is 39.05 S cm² molâ»Â¹ and Lambda_mâ° = 390.5 S cm² mol^{-1 ? These values define the system as per NCERT data. Formula: α = Lambda_m/Lambda_mâ° = 39.05/390.5 = 0.1 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: A solution is made by mixing 30 mL of methanol ( CH₃OH ) and 70 mL of water, with a total volume of 95 mL. What is the volume percentage of methanol? (Density of methanol = 0.792 g/mL) These values define the system as per NCERT data. Formula: Volume % = fracVolume of methanolTotal volume × 100. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given volume of methanol = 30 mL, total volume = 95 mL. Volume % = 30/95 × 100 = 31.58% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.
Given: A reaction’s rate increases by a factor of 8 when [A] is doubled and [B] is doubled. If the order with respect to B is 1, what is the order with respect to A? These values define the system as per NCERT data. Formula: Rate = k[A]^n[B]^m, m = 1, 8 = 2^n × 2¹. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 8 = 2^{n+1, n + 1 = 3, n = 2 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: A material with susceptibility chi = 3 × 10â»â´ has a relative permeability μ_r of: These values define the system as per NCERT data. Formula: μ_r = 1 + chi. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: chi = 3 × 10â»â´. Substitute: μ_r = 1 + 3 × 10â»â´= 1.0003 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.
Co shows +2, +3, and +4, with +4 being the maximum (e.g., in CoOâ‚‚ ), though +3 is more common. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Câ‚‚Hâ‚‚ has a triple bond (1 sigma, 2 pi) between carbons and 2 single bonds (2 sigma) to hydrogens. Total sigma bonds = 1 + 2 = 3. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Given: A hydrogen atom absorbs a photon of energy 12.09 eV from the ground state. To which energy level does it jump? (Use E_n = -13.6/n² eV ) These values define the system as per NCERT data. Formula: E_1 = -13.6 eV. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: E_n = -13.6 + 12.09 = -1.51 eV . -1.51 = -13.6/n² Rightarrow n² = 9 Rightarrow n = 3 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.
Adenine pairs with thymine via two hydrogen bonds in DNA, contributing to the stability of the double helix. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Given: What is the number of unpaired electrons in [FeF₆]^{3- ? These values define the system as per NCERT data. Formula: Fe³⺠( dâµ ) with weak field F^- in an octahedral field is high spin ( t_{2g³ e_g² ), with 5 unpaired electrons.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Given: What is the pH of a 0.004 M Ca(OH)2 solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 2 × 0.004 = 0.008 M, pOH = -log(0.008) approx 2.1. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.1 = 11.9 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.
[MnBrâ‚„]^{2- (Mn²âº, 4 ligands) adopts tetrahedral geometry due to sp³ hybridization with weak field Br^-, unlike the octahedral or square planar options.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Chemical Bonding and Molecular Structure, Topic: Bonding theories, VSEPR and hybridization.
