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CHEMISTRY

Here you will find chemistry questions covering chemical bonding, periodic trends, reaction types and numerical calculations. The set is meant for timed practice or slower topic review, whichever suits your study stage. Answers are provided so you can trace an error back to the concept behind it.

45 questions

Which amine can be synthesized from CH₃CH₂CH₂Br using Gabriel phthalimide synthesis?

Gabriel phthalimide synthesis converts primary alkyl halides like CH₃CH₂CH₂Br to primary amines, yielding CH₃CH₂CH₂NH₂ (propan-1-amine). This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

Which complex produces 1 mole of AgCl per mole when treated with excess AgNO₃ ?

[CoCl₂(NH₃)4]Cl has one ionizable Cl^- outside the coordination sphere, yielding 1 mole of AgCl, while the two inside are non-ionizable. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the oxidation number of oxygen in OF₂ ?

In OF₂, F is -1 (more electronegative), sum is zero: x + 2(-1) = 0, x - 2 = 0, x = +2 . This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

The oxidation state of cobalt in CoCl₂ is:

In CoCl₂, Cl = -1 (2 chlorines = -2). For neutrality, Co = +2. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the oxidation state of cobalt in [Co(en)2Cl₂]Cl ?

Given: What is the oxidation state of cobalt in [Co(en)2Cl₂]Cl ? Formula: The complex charge is +1 (balanced by 1 Cl⁻), so Co’s oxidation state is x - 2 = +1, x = +3 .. Substitution & Calculation: In [Co(en)2Cl₂]+, 2 en are neutral, 2 Cl^- contribute -2. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Electrochemistry (Latest NCERT 2026-27), Topic: Faraday's laws, charge required to reduce Al³⁺, 3F = 3 × 96500 C

What is the oxidation state of chromium in the dichromate ion Cr₂O₇^{2- ?

Given: What is the oxidation state of chromium in the dichromate ion Cr₂O₇^{2- ? Formula: In Cr₂O₇^{2-, O = -2 (7 oxygens = -14). Substitution & Calculation: Let Cr = x. Then, 2x - 14 = -2, so 2x = 12, x = +6 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

A reaction follows Rate = k[A][B]² with k = 0.1 L² mol^{-2 s^{-1, [A] = 0.2 M, and [B] = 0.4 M. What is the rate in mol

Given: A reaction follows Rate = k[A][B]² with k = 0.1 L² mol^{-2 s^{-1, [A] = 0.2 M, and [B] = 0.4 M. What is the rate in mol L^{-1 s^{-1 ? Formula: Rate = k[A][B]² = 0.1 × 0.2 × (0.4)² = 0.1 × 0.2 × 0.16 = 0.0032 .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

Calculate the boiling point elevation of a solution containing 9 g of urea ( NH₂CONH₂ ) in 200 g of water. ( K_b = 0.52

Given: Calculate the boiling point elevation of a solution containing 9 g of urea ( NH₂CONH₂ ) in 200 g of water. ( K_b = 0.52 K kg/mol, Molar mass of urea = 60 g/mol ) Formula: Moles of urea = 9/60 = 0.15 mol. Substitution & Calculation: Molality = 0.15/0.2 = 0.75 mol/kg . Δ T_b = 0.52 × 0.75 = 0.39 K . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Solutions (Latest NCERT 2026-27), Topic: Colligative properties, ΔT_b = K_b·m, urea NH₂CONH₂ example

For 2NO₂(g) N₂(g) + 2O₂(g), K_c = 0.25 at 600 K. If initial [NO₂] = 0.4 M, what is [O₂] at equilibrium?

Given: For 2NO₂(g) N₂(g) + 2O₂(g), K_c = 0.25 at 600 K. If initial [NO₂] = 0.4 M, what is [O₂] at equilibrium? Formula: Let [N₂] = x, [O₂] = 2x, [NO₂] = 0.4 - 2x. Substitution & Calculation: K_c = frac[N₂][O₂]²[NO₂]² = x (2x)²/(0.4 - 2x)² = 0.25 . 4x³/(0.4 - 2x)² = 0.25, solve: x approx 0.05, 2x = 0.1 M. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the standard ll potential for a galvanic ll where Sn(s) is oxidized to Sn²⁺(aq) and Cu²⁺(aq) is reduced to Cu(s)

Given: What is the standard ll potential for a galvanic ll where Sn(s) is oxidized to Sn²⁺(aq) and Cu²⁺(aq) is reduced to Cu(s), given their standard reduction potentials are -0.14 V and 0.34 V respectively? Formula: E_{ll⁰ = E_{cathode⁰ - E_{anode⁰. Substitution & Calculation: For Sn(s) → Sn²⁺(aq) + 2e⁻ (anode) and Cu²⁺(aq) + 2e⁻ → Cu(s) (cathode): E_{ll⁰ = 0.34 - (-0.14) = 0.48 V . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

The K_p for H₂(g) + CO₂(g) H₂O(g) + CO(g) is 0.25 at 1000 K. What is K_c if R = 0.0821 L · atm · mol^{-1 · K^{-1 ?

Given: The K_p for H₂(g) + CO₂(g) H₂O(g) + CO(g) is 0.25 at 1000 K. What is K_c if R = 0.0821 L · atm · mol^{-1 · K^{-1 ? Formula: Δ n = (1 + 1) - (1 + 1) = 0, so K_p = K_c (RT)^{Δ n = K_c. Substitution & Calculation: Thus, K_c = K_p = 0.25 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the EMF of a ll with Fe(s) | Fe²⁺(0.01 M) || H⁺(1 M) | H₂(g, 1 bar) | Pt(s) at 298 K, given E_{Fe^{2+/Fe⁰ = -0.4

Given: What is the EMF of a ll with Fe(s) | Fe²⁺(0.01 M) || H⁺(1 M) | H₂(g, 1 bar) | Pt(s) at 298 K, given E_{Fe^{2+/Fe⁰ = -0.44 V and E_{H^{+/H_2⁰ = 0 V ? Formula: E_{ll⁰ = 0 - (-0.44) = 0.44 V, n = 2. Substitution & Calculation: E_{ll = E_{ll⁰ - 0.059/2 log frac[Fe^{2+][H^{+]² . Q = 0.01/1² = 0.01, log Q = -2 . E_{ll = 0.44 - 0.059/2 × (-2) = 0.44 + 0.059 = 0.499 V approx 0.50 V . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.