Practice question

Given: For 2NO₂(g) <=> N₂(g) + 2O₂(g), K_c = 0.25 at 600 K. If initial [NO₂] = 0.4 M, what is [O₂] at equilibrium? Formula: Let [N₂] = x, [O₂] = 2x, [NO₂] = 0.4 - 2x. Substitution & Calculation: K_c = frac[N₂][O₂]²[NO₂]² = x (2x)²/(0.4 - 2x)² = 0.25 . 4x³/(0.4 - 2x)² = 0.25, solve: x approx 0.05, 2x = 0.1 M. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.