If a small value of capacitance is connected in parallel with a large value, the combined capacitance will be:
Parallel C_total=C1+C2≈large+small slightly greater than large value.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
Electrostatics 1
The Electrostatics 1 category gathers introductory physics questions focused on electrostatic phenomena. Topics include electric charge, Coulomb’s law, electric fields, potential difference, and basic problem‑solving techniques. Use these items to build a solid foundation before tackling more advanced electrostatics concepts.
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The bad conductor of heat is also known as-
Bad conductor of heat is insulator, also bad conductor of electricity generally.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
Find the equivalent capacitance between A and B: [Image: https://www.selfstudys.com/uploads/external-images/uDU56tUd1Hnb
Series 1/C=Σ1/Ci, parallel C=ΣCi, reduce network stepwise.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
A spherical drop of capacitance 1 μF is broken into eight drops of equal radius. Then, the capacitance of each small dro
Capacitance ∝ radius, R_large=2 R_small for 8 drops, C_small=0.5 μF.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
The electric polarization is-
Polarization P dipole moment per unit volume induced by external field.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
There is a uniform electric field of intensity E which is as shown. How many labelled points have the same electric pote
Equipotential lines perpendicular to uniform E; points along perpendicular have same potential.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
What is the angle between the electric field and tangent to the equipotential surface?
E perpendicular to equipotential surface, angle 90°, E=-∇V.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
The charges Q + q and + q are placed at the vertices of an equilateral triangle of side l. If the net electrostatic pote
Potential at centroid: V=kΣq/r, sum zero condition gives relation between Q and q.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
A charge particle of charge 25 × 10 -10 C is placed at a point. Find the magnitude of electric potential at a point whic
V=kq/r=9e9*25e-10/0.05=45 V approx per V=kq/r.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
Consider the following statements: A. The electric potential due to a dipole at its axial point is zero. B. The electric
Axial potential non-zero V=kp/r^2, equatorial zero; axial field stronger than equatorial.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
The potential of a large liquid drop when eight liquid drops are combined is 20 V. Then the potential of each single dro
V_large=n^{2/3} V_small, n=8, 20=4 V_small => V_small=5 V per charge conservation.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
The work done against --------- gets stored potential energy in an electric field ?
Work done against electric field stores as electric potential energy.
Ref: NCERT Physics Class 12 Chapter 1 Electric Charges and Fields
