What is the oxidation number of niobium in NbCl₅?
Let Nb = x. Cl = -1. Equation: x + 5(-1) = 0, x - 5 = 0, x = +5.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Latest questions in this category.
Let Nb = x. Cl = -1. Equation: x + 5(-1) = 0, x - 5 = 0, x = +5.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let C = x. O = -2. Equation: x + 2(-2) = 0, x - 4 = 0, x = +4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
H₂O₂ (O: -1 to -2 in H₂O) gains electrons, oxidizing Fe (+2 to +3).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let N = x. H = +1. Equation: 2x + 4(+1) = 0, 2x + 4 = 0, x = -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Cr (+6 in Cr₂O₇²−) to +3 in CrCl₃: 4 Cr gain 12 electrons. Cl (-1 to 0): 6 Cl lose 12 electrons. Total = 12.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let Cl = x. H = +1, O = -2. Equation: +1 + x + 4(-2) = 0, 1 + x - 8 = 0, x = +7.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let Tc = x. O = -2. Equation: 2x + 7(-2) = 0, 2x - 14 = 0, x = +7.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
In 3HNO₂ → HNO₃ + 2NO + H₂O, N (+3) in HNO₂ is oxidized to +5 in HNO₃ and reduced to +2 in NO, a disproportionation.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
In 2Co + Br₂ → 2CoBr, Co (0 to +1) loses electrons to reduce Br (0 to -1), with no oxygen involved.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The oxidizing agent is reduced. O₂ (0) gains electrons to become O₂²− (-1 in peroxide), oxidizing K.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The reducing agent is oxidized. Cl (0 in Cl₂) becomes +5 in NaClO₃ and -1 in NaCl; Cl₂ reduces itself.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The reducing agent donates electrons. Mg (0) loses electrons to form Mg²⁺ (+2), reducing H+.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength