What is the oxidation number of niobium in NbCl₅?
Let Nb = x. Cl = -1. Equation: x + 5(-1) = 0, x - 5 = 0, x = +5.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
This category explains how to identify oxidizing and reducing agents in redox reactions and how to compare their strength. Learn the factors that influence their reactivity and apply this knowledge to solve chemical problems.
Let Nb = x. Cl = -1. Equation: x + 5(-1) = 0, x - 5 = 0, x = +5.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let C = x. O = -2. Equation: x + 2(-2) = 0, x - 4 = 0, x = +4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
H₂O₂ (O: -1 to -2 in H₂O) gains electrons, oxidizing Fe (+2 to +3).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let N = x. H = +1. Equation: 2x + 4(+1) = 0, 2x + 4 = 0, x = -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Cr (+6 in Cr₂O₇²−) to +3 in CrCl₃: 4 Cr gain 12 electrons. Cl (-1 to 0): 6 Cl lose 12 electrons. Total = 12.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let Cl = x. H = +1, O = -2. Equation: +1 + x + 4(-2) = 0, 1 + x - 8 = 0, x = +7.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
Let Tc = x. O = -2. Equation: 2x + 7(-2) = 0, 2x - 14 = 0, x = +7.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
In 3HNO₂ → HNO₃ + 2NO + H₂O, N (+3) in HNO₂ is oxidized to +5 in HNO₃ and reduced to +2 in NO, a disproportionation.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
In 2Co + Br₂ → 2CoBr, Co (0 to +1) loses electrons to reduce Br (0 to -1), with no oxygen involved.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The oxidizing agent is reduced. O₂ (0) gains electrons to become O₂²− (-1 in peroxide), oxidizing K.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The reducing agent is oxidized. Cl (0 in Cl₂) becomes +5 in NaClO₃ and -1 in NaCl; Cl₂ reduces itself.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength
The reducing agent donates electrons. Mg (0) loses electrons to form Mg²⁺ (+2), reducing H+.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Oxidizing and Reducing Agents and Strength