This category focuses on questions related to the force of gravity, gravitational fields, and how mass and distance influence gravitational interactions. It includes applications of Newton's law of gravitation.
Pav = FA, F = mg = 60×10 = 600N. Total area A = 2×25×10−4 = 5.0×10−3m2. Pav = 6005.0×10−3 = 1.2×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.2 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 45×9.8 = 441N. Total area A = 2×18×10−4 = 3.6×10−3m2. Pav = 4413.6×10−3 = 1.225×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.225 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 70×9.8 = 686N. Total area A = 2×16×10−4 = 3.2×10−3m2. Pav = 6863.2×10−3 = 2.14375×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.14 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 55×10 = 550N. Total area A = 2×14×10−4 = 2.8×10−3m2. Pav = 5502.8×10−3 = 1.964×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.96 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 75×9.8 = 735N. Total area A = 2×24×10−4 = 4.8×10−3m2. Pav = 7354.8×10−3 = 1.53125×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.53 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
P = FA, F = 40×10 = 400N. Total area A = 2×12×10−4 = 2.4×10−3m2. P = 4002.4×10−3≈1.67×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.67 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 65×10 = 650N. Total area A = 2×20×10−4 = 4.0×10−3m2. Pav = 6504.0×10−3 = 1.625×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.625 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
When the viscous force (from Stokes’ law) plus buoyant force equals the gravitational force, the net force becomes zero, and the object reaches terminal velocity, moving at a constant speed, as explained in the chapter.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.
Pav = FA, F = mg = 60×10 = 600N. Total area A = 2×15×10−4 = 3×10−3m2. Pav = 6003×10−3 = 2×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Elongation: ΔL = (F L) / (A Y). Ratio: (ΔLsteel)/(ΔLcopper) = Ycopper / Ysteel = (1.1 × 1011) / (2 × 1011) = 11/20 = 0.55. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.55. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: University Physics, Chapter 17: Thermal Expansion.
Kepler’s third law: Tp2TE2 = ap3aE3. TE = 1year, Tp = 5years, aE = 1.5×1011m. 5212 = ap3(1.5×1011)3. 25 = ap33.375×1033. ap3 = 25×3.375×1033 = 8.4375×1034. ap = (8.4375×1034)1/3≈4.39×1011m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.4 × 10¹¹ m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.
Angular momentum conservation (mrv = constant) implies that at perihelion (smaller r), the speed v is greater than at aphelion (larger r), as derived from Kepler’s second law. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Conservation of angular momentum. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.
