What is the oxidation number of chlorine in Cl₂O?
Let Cl = x. O = -2. Equation: 2x + (-2) = 0, 2x = 2, x = +1.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
This category covers how redox reactions and disproportionation apply in chemical processes, industrial uses, and everyday phenomena. Learn to identify and solve problems involving these concepts with practical examples.
Let Cl = x. O = -2. Equation: 2x + (-2) = 0, 2x = 2, x = +1.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
P (0) is oxidized to +3 in H₃PO₃ and reduced to -3 in PH₃; P reduces itself in this disproportionation.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
In Mg(OH)2 + 2HCl → MgCl₂ + 2H₂O, no element changes oxidation state (Mg: +2, H: +1, O: -2, Cl: -1).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
S (-2 in H₂S) becomes 0 in S, losing electrons.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
TeO₂ (Te: +4 to 0) gains electrons, reduced by H₂ (0 to +1).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
In OF₂, O is less electronegative than F (-1). Equation: x + 2(-1) = 0, x = +2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
Reduction involves electron gain. In 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄, Fe (+3) gains an electron to become Fe (+2).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
In CuO + H₂ → Cu + H₂O, Cu (+2 to 0) is reduced, and H (0 to +1) is oxidized.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
The oxidizing agent accepts electrons. Cl₂ (0) gains electrons to become Cl− (-1), oxidizing Na.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
In 3Br₂ + 6NaOH → 5NaBr + NaBrO₃ + 3H₂O, Br (0) is oxidized to +5 in NaBrO₃ and reduced to -1 in NaBr.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
Let the oxidation number of S be x. H = +1, O = -2. Equation: 2(+1) + x + 4(-2) = 0. Solving: 2 + x - 8 = 0, x = +6.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
In 3S + 6NaOH → 2Na₂S + Na₂SO₃ + 3H₂O, S (0) is oxidized to +4 in Na₂SO₃ and reduced to -2 in Na₂S.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation