What is the oxidation number of carbon in CH₄?
Let C = x. H = +1. Equation: x + 4(+1) = 0, x + 4 = 0, x = -4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Latest questions in this category.
Let C = x. H = +1. Equation: x + 4(+1) = 0, x + 4 = 0, x = -4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
C in CO₂: +4. In CH₂O: x + 2(+1) + (-2) = 0, x = 0, which is lower.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In S₈ + 8O₂ → 8SO₂, S (0) is oxidized to +4, and O (0) is reduced to -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
O (-1 in H₂O₂) becomes -2 in H₂O, gaining electrons.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Oxidation involves electron loss. S (-2 in H₂S) becomes 0 in S, losing electrons.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Let S = x. H = +1. Equation: 2(+1) + x = 0, 2 + x = 0, x = -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
C (+3 in C₂O₄²−) to +4 in CO₂ is oxidized; Mn (+7 to +2) is reduced.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
KI (I: -1 to 0 in I₂) loses electrons, reducing Br₂ (0 to -1).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Let Os = x. O = -2. Equation: x + 4(-2) = 0, x - 8 = 0, x = +8.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In 2Al + 3Cl₂ → 2AlCl₃, Al (0) loses electrons to become Al₃+ (+3).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Br₂ (0) is reduced to -1 in NaBr and oxidized to +5 in NaBrO₃, acting as its own oxidizing agent.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In 4Na + O₂ → 2Na₂O, Na gains oxygen to form Na₂O, an oxidation process.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells