Kinematic Equations and Uniformly Accelerated Motion

Kinematic Equations and Uniformly Accelerated Motion

Two stones are dropped from a height of 80m, 1.5s apart. How long after the second stone is released do they meet if the

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 4 s. This confirms option A as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A rocket ascends with an acceleration of 4m/s2 for 6s, then its engines shut off. How long does it take to reach its max

At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=4 m/s and g=10 m/s², h=0.8 m. This matches option A (8 s). Other options do not satisfy v²=u²+2as with correct signs.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A ball is thrown upwards with a speed of 38m/s. What is its velocity after 3s? (Take g\=10m/s2)

Use v=v0+at. Here, v0=38m/s, a=−10m/s2, t=3s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 8 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

Two stones are dropped from a height of 125m, with a 2s interval between them. How far apart are they when the second st

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 80 m. This confirms option C as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A stone falls freely from rest and reaches a velocity of 14.7m/s. How long did it fall? (Take g\=9.8m/s2)

Use v=v0+gt. Here, v0=0, v=14.7m/s, g=9.8m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 2 s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A bike accelerates uniformly from rest to 20m/s over a distance of 40m. What is its acceleration?

Use v2=v02+2ax. Here, v0=0, v=20m/s, x=40m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 40 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A stone is dropped from a height of 45m on a planet where it takes 3s to reach the ground. What is the acceleration due

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 10 m/s². This confirms option D as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A train moving at 72km/h passes a pole in 9s. If it decelerates uniformly to rest in 30s after passing the pole, what is

Speed: 72km/h=20m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 180 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A stone falls from a height and covers 58.8m in the last 1.2s of its fall. What is the total height? (Take g\=9.8m/s2)

Total time = t, last 1.2 s: 58.8=9.8t−4.9(t−1.2)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 210 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A car traveling at 54km/h comes to rest in 10s with uniform deceleration. What is the magnitude of the deceleration?

Convert speed: 54km/h=54⋅10003600=15m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 1.5 m/s² as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A cyclist moves with a constant speed of 5m/s for 20s. What is the distance covered?

For constant speed, distance x=vt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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Kinematic Equations and Uniformly Accelerated Motion

A particle moves at 18m/s and decelerates at 3m/s2 until its speed halves, then accelerates at 2m/s2 to its original spe

Phase 1: 9=18−3t⇒t1=3s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 s as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

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