Builds on Part 1 with more complex reactions involving nitrous acid and diazonium salts, including synthetic applications and mechanisms.
Pentanamide (CH₃CH₂CH₂CH₂CONH₂) loses one carbon in the Hoffmann reaction to form butan-1-amine (CH₃CH₂CH₂CH₂NH₂), as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Gabriel synthesis produces primary aliphatic amines like CH₃CH₂NH₂ from alkyl halides, not aromatic amines, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Gabriel phthalimide synthesis selectively forms primary amines like CH₃CH₂NH₂ without secondary byproducts, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Aromatic amines like C₆H₅NH₂ cannot be prepared by Gabriel synthesis, which is limited to aliphatic primary amines, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Gabriel phthalimide synthesis produces only primary amines by reacting phthalimide with an alkyl halide, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Gabriel phthalimide synthesis selectively produces primary amines by reacting phthalimide with an alkyl halide, followed by hydrolysis, avoiding mixtures of secondary and tertiary amines seen in ammonolysis.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Gabriel phthalimide synthesis uses phthalimide with an alkyl halide to selectively prepare primary amines, as detailed in the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Ammonolysis of CH₃CH₂Cl with excess NH₃ favors the formation of the primary amine CH₃CH₂NH₂ (ethylamine), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Methylamine (CH₃NH₂) is formed directly from CH₃Cl and NH₃ in one step via ammonolysis, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Benzyl chloride (C₆H₅CH₂Cl) with excess NH₃ forms benzylamine (C₆H₅CH₂NH₂) via ammonolysis, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
1-Chloropropane (CH₃CH₂CH₂Cl) undergoes ammonolysis with NH₃ to form propan-1-amine (CH₃CH₂CH₂NH₂), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Benzyl chloride (C₆H₅CH₂Cl) with NH₃ forms benzylamine (C₆H₅CH₂NH₂), which reacts with two CH₃Cl to form C₆H₅CH₂N(CH₃)₂ (N,N-dimethylbenzylamine).
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
