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Induced EMF Due to Change in Magnetic Field

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A coil is placed near a current-carrying wire. If the current in the wire is suddenly switched off, what happens to the

**Uniform field change** in coil produces emf proportional to area and turns, for circular coil radius 0.16 m area πr²=0.0804 m², B 0.12 T deformed to wire in 0.6 s, ΔΦ=0.12×0.0804=0.00965 Wb, e=0.00965/0.6=0.0161 V, illustrating area change also induces emf. When the current is switched off, the magnetic field due to the wire collapses, reducing the magnetic flux through the coil from some value to zero. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result Increases

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A coil of 200 turns is placed in a field that decreases from 0.05 T to 0 in 0.4 s. If the area is 0.02 m², what is the i

**Field decreasing to zero** induces emf trying to maintain field, current direction such that its field adds to original. For 150 turns area 0.06 m² B 0.14 T to zero in 0.3 s, e=150×0.06×0.14/0.3=4.2 V, as earlier, showing linear dependence on N, A, ΔB/Δt. Δ Φ = B A = 0.05 × 0.02 = 0.001 Wb . ε = N (Δ Φ/Δ t) = 200 × (0.001/0.4) = 0.5 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U =

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A coil of 50 turns and area 0.06 m² is in a 0.15 T field that drops to zero in 0.3 s. What is the induced emf?

**Induced emf due to B change** e = -N A dB/dt, N turns, A area (m²), dB/dt rate of change of field (T/s). For 110 turns area 0.035 m² B 0.09 T to 0 in 0.5 s, dB/dt=0.18 T/s, e=110×0.035×0.18=0.693 V, direction opposes decrease via Lenz's law. Δ Φ = B A = 0.15 × 0.06 = 0.009 Wb . ε = N (Δ Φ/Δ t) = 50 × (0.009/0.3) = 50 × 0.03 = 1.5 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀

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A conducting loop is rotated in a uniform magnetic field. The induced emf depends on the rate of change of what physical

**Uniform field change** in coil produces emf proportional to area and turns, for circular coil radius 0.16 m area πr²=0.0804 m², B 0.12 T deformed to wire in 0.6 s, ΔΦ=0.12×0.0804=0.00965 Wb, e=0.00965/0.6=0.0161 V, illustrating area change also induces emf. Faraday’s law states that the induced emf is proportional to the rate of change of magnetic flux through the loop, which varies as the loop rotates. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result Magnetic

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A coil of 130 turns experiences a magnetic flux change from 0 to 0.06 Wb in 0.12 s. What is the induced emf?

**Field decreasing to zero** induces emf trying to maintain field, current direction such that its field adds to original. For 150 turns area 0.06 m² B 0.14 T to zero in 0.3 s, e=150×0.06×0.14/0.3=4.2 V, as earlier, showing linear dependence on N, A, ΔB/Δt. ε = N (Δ Φ/Δ t) . Δ Φ = 0.06 Wb , Δ t = 0.12 s , N = 130 . ε = 130 × (0.06/0.12) = 130 × 0.5 = 65 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L

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A coil is placed near a current-carrying solenoid. The induced emf in the coil is zero when the solenoid’s current is in

**Induced emf due to B change** e = -N A dB/dt, N turns, A area (m²), dB/dt rate of change of field (T/s). For 110 turns area 0.035 m² B 0.09 T to 0 in 0.5 s, dB/dt=0.18 T/s, e=110×0.035×0.18=0.693 V, direction opposes decrease via Lenz's law. A constant current produces a steady magnetic field, resulting in no change in flux through the coil and thus no induced emf. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L

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A coil of 280 turns rotates at 80 rad/s in a 0.06 T field. If the area is 0.01 m², what is the maximum emf?

**Uniform field change** in coil produces emf proportional to area and turns, for circular coil radius 0.16 m area πr²=0.0804 m², B 0.12 T deformed to wire in 0.6 s, ΔΦ=0.12×0.0804=0.00965 Wb, e=0.00965/0.6=0.0161 V, illustrating area change also induces emf. ε₀ = N B A ω = 280 × 0.06 × 0.01 × 80 = 13.44 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result 13.44 V follows, reflecting Faraday's law and Lenz's opposition.

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A coil of 150 turns and area 0.05 m² is in a field that increases from 0 to 0.06 T in 0.3 s. What is the induced emf?

**Field decreasing to zero** induces emf trying to maintain field, current direction such that its field adds to original. For 150 turns area 0.06 m² B 0.14 T to zero in 0.3 s, e=150×0.06×0.14/0.3=4.2 V, as earlier, showing linear dependence on N, A, ΔB/Δt. Δ Φ = B A = 0.06 × 0.05 = 0.003 Wb . ε = N (Δ Φ/Δ t) = 150 × (0.003/0.3) = 150 × 0.01 = 1.5 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M =

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A circular coil of radius 9 cm and 200 turns rotates at 50 rad/s in a 0.03 T field. What is the maximum emf induced?

**Induced emf due to B change** e = -N A dB/dt, N turns, A area (m²), dB/dt rate of change of field (T/s). For 110 turns area 0.035 m² B 0.09 T to 0 in 0.5 s, dB/dt=0.18 T/s, e=110×0.035×0.18=0.693 V, direction opposes decrease via Lenz's law. A = π r² = 3.14 × (0.09)² = 0.0254 m² . ε₀ = N B A ω = 200 × 0.03 × 0.0254 × 50 = 7.62 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l,

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A coil of 100 turns and area 0.02 m² is rotated at 50 Hz in a 0.05 T field. What is the maximum emf?

**Induced emf due to B change** e = -N A dB/dt, N turns, A area (m²), dB/dt rate of change of field (T/s). For 110 turns area 0.035 m² B 0.09 T to 0 in 0.5 s, dB/dt=0.18 T/s, e=110×0.035×0.18=0.693 V, direction opposes decrease via Lenz's law. ω = 2π v = 2π × 50 = 100π rad/s . ε₀ = N B A ω = 100 × 0.05 × 0.02 × 100π = 31.4 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l,

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A coil of 220 turns rotates at 70 rad/s in a 0.05 T field. If the area is 0.025 m², what is the maximum emf?

**Induced emf due to B change** e = -N A dB/dt, N turns, A area (m²), dB/dt rate of change of field (T/s). For 110 turns area 0.035 m² B 0.09 T to 0 in 0.5 s, dB/dt=0.18 T/s, e=110×0.035×0.18=0.693 V, direction opposes decrease via Lenz's law. ε₀ = N B A ω = 220 × 0.05 × 0.025 × 70 = 19.25 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I², result 19.25 V

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A coil of 90 turns and area 0.03 m² is in a field that increases from 0 to 0.06 T in 0.3 s. What is the induced emf?

**Uniform field change** in coil produces emf proportional to area and turns, for circular coil radius 0.16 m area πr²=0.0804 m², B 0.12 T deformed to wire in 0.6 s, ΔΦ=0.12×0.0804=0.00965 Wb, e=0.00965/0.6=0.0161 V, illustrating area change also induces emf. Δ Φ = B A = 0.06 × 0.03 = 0.0018 Wb . ε = N (Δ Φ/Δ t) = 90 × (0.0018/0.3) = 90 × 0.006 = 0.54 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U =

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