NEET MOCK TEST 7

CHEMISTRY

What is the mole fraction of NaCl in a solution containing 5.85 g of NaCl and 90 g of water? (Molar masses: NaCl = 58.5

Given: What is the mole fraction of NaCl in a solution containing 5.85 g of NaCl and 90 g of water? (Molar masses: NaCl = 58.5 g/mol, H₂O = 18 g/mol) These values define the system as per NCERT data. Formula: Moles of NaCl = 5.85 / 58.5 = 0.1 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Moles of H₂O = 90 / 18 = 5 mol. Total moles = 0.1 + 5 = 5.1. Mole fraction = 0.1 / 5.1 ≈ 0.0196. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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CHEMISTRY

A gaseous reaction follows Rate = k p_A² with k = 0.2 atm^{-1 s^{-1 and p_A = 0.5 atm . What is the rate in atm s^{-1 ?

Given: A gaseous reaction follows Rate = k p_A² with k = 0.2 atm^{-1 s^{-1 and p_A = 0.5 atm . What is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A² = 0.2 × (0.5)² = 0.2 × 0.25 = 0.05 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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BOTANY

What is the expected phenotypic ratio of a dihybrid cross in F2 generation if genes show complete dominance?

A dihybrid cross with complete dominance results in a phenotypic ratio of 9:3:3:1 in the F2 generation. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Biology Textbook for Class XI and XII (Botany section), Chapter: Morphology and Anatomy of Flowering Plants, Topic: Plant structure and tissue systems.

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PHYSICS

A neutron ( 1 u ) moving at 2 × 10⁶ m/s collides elastically with a carbon nucleus ( 12 u ). What fraction of its kin

Given: A neutron ( 1 u ) moving at 2 × 10⁶ m/s collides elastically with a carbon nucleus ( 12 u ). What fraction of its kinetic energy is retained? These values define the system as per NCERT data. Formula: Fraction retained f_1 = ( m_1 - m_2/m_1 + m_2 )² = ( 1 - 12/1 + 12 )² = ( -11/13 )² = 121/169 approx 0.716 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

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CHEMISTRY

How many pi bonds are present in the Câ‚‚Hâ‚‚ molecule?

Câ‚‚Hâ‚‚ has a triple bond between carbons (1 sigma, 2 pi), totaling 2 pi bonds. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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PHYSICS

In a full-wave rectifier, the number of diodes typically used with a ntre-tap transformer is:

A full-wave rectifier with a ntre-tap transformer uses two diodes, each conducting during alternate half-cycles, to rectify both positive and negative halves of the AC input.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.

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CHEMISTRY

The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K k

Given: The boiling point elevation of a 0.15 m aqueous KCl solution is 0.156 K. What is the van't Hoff factor? ( K_b = 0.52 K kg/mol ) These values define the system as per NCERT data. Formula: Δ T_b = i · K_b · m. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 0.156 = i × 0.52 × 0.15 . i = 0.156/0.52 × 0.15 = 0.156/0.078 = 2 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

The number of unpaired electrons in Ti^{3+ (Z = 22) is:

Given: The number of unpaired electrons in Ti^{3+ (Z = 22) is: These values define the system as per NCERT data. Formula: Ti: 3d² 4s². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Ti^{3+ : 3d¹ (loses 2 from 4s, 1 from 3d). 1 unpaired electron. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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CHEMISTRY

How many electrons are transferred in the reduction of 1 mol of Oâ‚‚ to Hâ‚‚O in acidic medium?

Reaction: Oâ‚‚ + 4H+ + 4e- -> 2Hâ‚‚O . 4 electrons per mole of Oâ‚‚. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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CHEMISTRY

What is the primary valence of nickel in NiCl₂ · 6H₂O ?

In NiCl₂ · 6H₂O, formulated as [Ni(H₂O)6]Cl₂, the primary valence is the oxidation state of Ni, satisfied by 2 ionizable Cl^- ions, so it is 2. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

The number of moles of Fe^{2+ oxidized by 1 mole of K₂Cr₂O₇ in acidic medium is:

Cr₂O₇^{2- + 14H^+ + 6Fe^{2+ -> 2Cr^{3+ + 6Fe^{3+ + 7H₂O . 1 mole K₂Cr₂O₇ oxidizes 6 moles Fe^{2+ . This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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CHEMISTRY

What is the pH of a solution with [OH-] = 2.5 × 10⁻² M?

Given: What is the pH of a solution with [OH-] = 2.5 × 10⁻² M? These values define the system as per NCERT data. Formula: pOH = -log(2.5 × 10⁻²) approx 1.6, pH = 14 - 1.6 = 12.4 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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