Practice question
Question
For Nâ‚‚(g) + Oâ‚‚(g) <=> 2NO(g), K_c = 0.02 at 1500 K. What is K_c for NO(g) <=> 1/2 Nâ‚‚(g) + 1/2 Oâ‚‚(g) ?
Explanation
Given:
For Nâ‚‚(g) + Oâ‚‚(g) <=> 2NO(g), K_c = 0.02 at 1500 K. What is K_c for NO(g) <=> 1/2 Nâ‚‚(g) + 1/2 Oâ‚‚(g) ?
These values define the system as per NCERT data.
Formula:
For the reverse halved reaction, K_c' = frac1sqrtK_c = frac1sqrt0.02 approx 7.07 ..
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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