Practice question
Question
How much time (in seconds) is required to deposit 0.635 g of copper from CuSO₄ solution using a current of 0.5 A? (Atomic mass of Cu = 63.5 g/mol, F = 96500 C/mol)
Explanation
Moles of Cu = (0.635/63.5) = 0.01 mol . Charge = 0.01 × 2 × 96500 = 1930 C . t = (Q/I) = (1930/0.5) = 3860 s .
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