Practice question
Question
The limiting molar conductivity of KBr is 151.8 S cm² mol⁻¹. If λ°K⁺ = 73.5 S cm² mol⁻¹ , what is λ°Br⁻ ?
Explanation
Lambdam° = λ°K⁺ + λ°Br⁻ . 151.8 = 73.5 + λ°Br⁻ , λ°Br⁻ = 78.3 S cm² mol⁻¹ .
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