The limiting molar conductivity of KBr is 151.8 S cm² mol⁻¹. If λ°K⁺ = 73.5 S cm² mol⁻¹ , what is λ°Br⁻ ?
Lambdam° = λ°K⁺ + λ°Br⁻ . 151.8 = 73.5 + λ°Br⁻ , λ°Br⁻ = 78.3 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
