A 0.3 M HCl solution is diluted by adding 400 mL of water to 100 mL of the original solution. What is the final molarity
M₁V₁ = M₂V₂. 0.3 × 100 = M₂ × (100 + 400). M₂ = (0.3 × 100)/500 = 0.06 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent