Practice question
Question
What volume of CO₂ at STP is produced when 11.2 g of C₅H₁₂ is burned completely? (Molar mass: C₅H₁₂ = 72 g/mol)
Explanation
Reaction: C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O. Moles of C₅H₁₂ = 11.2/72 ≈ 0.1556 mol. 1 mol produces 5 mol CO₂; 0.1556 mol produces 0.7778 mol. Volume = 0.7778 × 22.4 ≈ 17.42 L.
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