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#CO₂

15 public questions tagged with this topic.

Many microorganisms can’t use CO2 as their sole source of carbon as

The principle of core biological organization explains that structure-function relationships govern cellular processes. Hence Reduction of CO2 is an energy expensive process fits best because it integrates fundamental principles, as documented in authoritative sources on general biology.

Ref: Campbell et al., Biology, 11th Edition, Chapter 2, Chemical Basis of Life, discusses fundamental biological principles and molecular organization providing broad foundation for life sciences understanding.

Which of the following organisms typically get their carbon for biosynthesis from carbon dioxide

The principle of core biological organization explains that structure-function relationships govern cellular processes. Hence Ammonia oxidizing bacteria fits best because it integrates fundamental principles, as documented in authoritative sources on general biology.

Ref: Campbell et al., Biology, 11th Edition, Chapter 2, Chemical Basis of Life, discusses fundamental biological principles and molecular organization providing broad foundation for life sciences understanding.

A hydrocarbon with 9 σ bonds produces 5 moles of CO₂ per mole upon combustion. What is its molecular formula?

5 carbons (from 5 CO₂). CH₃CH₂CH₂CH₂CH₃ (pentane) has 9 σ (8 C-H, 1 C-C from single bonds), no π, and fits C₅H₁₂.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Fundamental Concepts - Reaction Mechanism - Fission and Reaction Intermediates

In the estimation of carbon and hydrogen, 0.25 g of a compound gave 0.66 g of CO₂ and 0.135 g of H₂O. What is the empiri

Mass of C = (12/44) × 0.66 = 0.18 g. Mass of H = (2/18) × 0.135 = 0.015 g. Ratio C:H = (0.18/12)/(0.015/1) = 1:1. Empirical formula = CH.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance

A 0.42 g sample of a hydrocarbon produces 1.32 g of CO₂ and 0.54 g of H₂O on complete combustion. What is its molecular

Mass of C ≈ 0.36 g; mass of H = 0.06 g. Total = 0.42 g. Moles: C = 0.03, H = 0.06; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 42/14 = 3; molecular formula = C₃H₆.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

What volume of CO₂ at STP is produced when 11.2 g of C₅H₁₂ is burned completely? (Molar mass: C₅H₁₂ = 72 g/mol)

Reaction: C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O. Moles of C₅H₁₂ = 11.2/72 ≈ 0.1556 mol. 1 mol produces 5 mol CO₂; 0.1556 mol produces 0.7778 mol. Volume = 0.7778 × 22.4 ≈ 17.42 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple