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Question

How many grams of H₂SO₄ are required to neutralize 8 g of NaOH completely? (Molar masses: H₂SO₄ = 98 g/mol, NaOH = 40 g/mol)

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Explanation

Reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. Moles of NaOH = 8/40 = 0.2 mol. 2 mol NaOH need 1 mol H₂SO₄; 0.2 mol needs 0.1 mol. Mass = 0.1 × 98 = 9.8 g.

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