Skip to content
Login Register

Practice question

MCQ

Question

A solution contains 23 g of methanol (molar mass = 32 g/mol) and 72 g of water. If 64 g of water is added, what is the new mole fraction of methanol?

Options

Choose one · Correct answer highlighted

Explanation

Moles of methanol = (23/32) ≈ 0.7188 . Initial moles of water = (72/18) = 4 . New moles of water = (72 + 64/18) = (136/18) ≈ 7.5556 . Total moles = 0.7188 + 7.5556 ≈ 8.2744 . Mole fraction = (0.7188/8.2744) ≈ 0.0869 .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic