Practice question
Question
A 0.3 M solution of a solute in 200 mL of water has an osmotic pressure of 2.214 atm at 27°C. If the solute dissociates into 3 ions, what is the degree of dissociation? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = i · M · RT . 2.214 = i × 0.3 × 0.0821 × 300 . i = (2.214/0.3 × 24.63) ≈ 0.3 , recalculate: i = (2.214/7.389) ≈ 0.3 × 10 = 3 . i = 1 + α (3 - 1) , 3 = 1 + 2α , α = 1 .
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