Practice question
Question
A 0.15 M solution of a solute in 500 mL of water has an osmotic pressure of 1.476 atm at 27°C. If the solute dissociates into 2 ions, what is the degree of dissociation? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = i · M · RT . 1.476 = i × 0.15 × 0.0821 × 300 . i = (1.476/0.15 × 0.0821 × 300) ≈ 0.4 , which is incorrect; recalculate: i = (1.476/0.15 × 24.63) ≈ 0.4 × 4 = 1.6 . i = 1 + α , 1.6 = 1 + α , α = 0.6 .
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