Which condition would cause the highest osmotic pressure?
Osmotic pressure pi is thermodynamically defined for ideal dilute solution by van't Hoff expression pi equals i times M times R times T, where i accounts for dissociation into ions, M molarity of total particles, R universal gas constant 0.082 liter atm per mol per K, T absolute temperature. Sodium chloride dissociates into two particles so i about two, doubling effective concentration. Consequently pi scales linearly with total osmolarity. Among listed options, 0.1 molar NaCl yields approximately 0.2 osmolar giving pi about 4.9 atm at 298 K, 0.5 molar yields 1.0 osmolar about 24.5 atm, 1.0 molar yields 2.0 osmolar about 49 atm, 1.5 molar yields 3.0 osmolar about 73 atm, assuming complete dissociation and ignoring activity coefficients. Hence highest concentration produces highest osmotic pressure provided temperature constant. Even though example marks 1.0 molar as answer, principle that osmotic pressure increases monotonically with molar concentration remains; 1.5 molar would generate greatest pressure as predicted from proportionality between solute particle number and colligative property.
Ref: Berg et al., Biochemistry, Chapter 2: Van't Hoff Osmotic Pressure Dependence on Concentration.