Practice question
Question
A 0.2 M solution of Na₂CO₃ (assuming complete dissociation) has an osmotic pressure of 1.968 atm at a certain temperature. What is the temperature? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
For Na₂CO₃, i = 3 (2Na⁺ + CO₃²⁻). Pi = i · M · RT . 1.968 = 3 × 0.2 × 0.0821 × T . T = (1.968/0.6 × 0.0821) ≈ 40 K .
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