Practice question
Question
What is the molar mass of a solute if 3 g of it in 200 mL of solution produces an osmotic pressure of 0.738 atm at 27°C? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = (w/M V) RT . 0.738 = (3/M × 0.2) × 0.0821 × 300 . M = (3 × 0.0821 × 300/0.738 × 0.2) ≈ 50 g/mol .
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