8 public questions tagged with this topic.
For Na₂CO₃, i = 3 (2Na⁺ + CO₃²⁻). Pi = i · M · RT . 1.968 = 3 × 0.2 × 0.0821 × T . T = (1.968/0.6 × 0.0821) ≈ 40 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
Pi = i · M · RT . Molarity = (0.05/0.5) = 0.1 M . 2.463 = i × 0.1 × 0.0821 × 300 . i = (2.463/0.1 × 24.63) ≈ 1 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
For MgCl₂, i = 3 (Mg²⁺ + 2Cl⁻). Pi = i · M · RT . 1.845 = 3 × 0.25 × 0.0821 × T . T = (1.845/0.75 × 0.0821) ≈ 30 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
Pi = MRT . Pi = 0.01 × 0.0821 × 300 ≈ 0.246 atm .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
For Na₂SO₄, i = 3 (2Na⁺ + SO₄²⁻). Pi = i · M · RT . 2.214 = 3 × 0.3 × 0.0821 × T . T = (2.214/0.9 × 0.0821) ≈ 30 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
For K₃PO₄, i = 4 (3K⁺ + PO₄³⁻). Pi = i · M · RT . 0.984 = 4 × 0.1 × 0.0821 × T . T = (0.984/0.4 × 0.0821) ≈ 30 K .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
Δ G = Δ H - TΔ S < 0, -150 - T(-0.5) < 0, 0.5T < 150, T < 300 K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Gibbs Energy and Gibbs Energy Change and Equilibrium
Photorespiration occurs in C₃ plants when O₂ concentration is high and CO₂ concentration is low, leading RuBisCO to function as an oxygenase instead of a carboxylase.
Ref: NCERT Class 11 Biology Chapter 11: Photosynthesis in Higher Plants Chemiosmotic Hypothesis and Factors Affecting Photosynthesis
