57 public questions tagged with this topic.
Lambdam = (kappa × 1000/c) = (0.00195 × 1000/0.015) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.00195 × 1000/0.015) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.006 × 1000/0.05) = 120 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.00141 × 1000/0.01) = 141 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.00141 × 1000/0.01) = 141 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Lambdam = (kappa × 1000/c) = (0.00325 × 1000/0.025) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Lambdam = (kappa × 1000/c) = (0.00325 × 1000/0.025) = 130 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
Total mass = 5 g + 45 g = 50 g. Mass % = (5/50) × 100 = 10% .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
Mass of solute = (10/100) × 50 = 5 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration
Moles of solute = (6/120) = 0.05 mol . Volume = 300 mL = 0.3 L. Molarity = (0.05/0.3) ≈ 0.1667 M .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Initial mass % = (25/25 + 75) × 100 = 25% . New mass % = 20% = (25/25 + 75 + w) × 100 . 0.2 (100 + w) = 25 , 100 + w = 125 , w = 25 g . Total mass = 100 + 25 = 125 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Δ Tb = Kb · m . 100.26 - 100 = 0.52 · m . m = (0.26/0.52) = 0.5 mol/kg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
