Practice question

Given: What is the mole fraction of glucose in a solution containing 18 g of glucose (C₆H₁₂O₆) and 72 g of water? (Molar masses: glucose = 180 g/mol, H₂O = 18 g/mol) These values define the system as per NCERT data. Formula: Moles of glucose = 18 / 180 = 0.1 mol. This is standard NCERT relation. Substitution & Calculation: Moles of H₂O = 72 / 18 = 4 mol. Total moles = 0.1 + 4 = 4.1. Mole fraction = 0.1 / 4.1 ≈ 0.0244. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.