Practice question

Given: A 1.5 M solution of KOH has a density of 1.06 g/mL. What is its molality? (Molar mass of KOH = 56 g/mol) These values define the system as per NCERT data. Formula: Mass of 1 L = 1060 g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of KOH = 1.5 × 56 = 84 g. Mass of water = 1060 - 84 = 976 g = 0.976 kg. Molality = 1.5 / 0.976 ≈ 1.54 m. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.