15 public questions tagged with this topic.
Benzene undergoes electrophilic substitution with chlorine to form chlorobenzene. This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Hydrocarbons, Topic: Aromatic hydrocarbons, benzene as example, Hückel rule and aromaticity.
Benzene has delocalized π -electrons and shows resonance, making it more stable. This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Hydrocarbons, Topic: Aromatic hydrocarbons, benzene as example, Hückel rule and aromaticity.
Phenol (C₆H₅OH) is reduced to benzene (C₆H₆) when heated with zinc dust, removing the -OH group as ZnO and H₂.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
Friedel-Crafts alkylation of benzene with CH₃Cl and AlCl₃ forms C₆H₅CH₃ (toluene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
Electrophilic substitution of benzene with chlorine and a Lewis acid (e.g., FeCl₃ ) replaces a hydrogen with chlorine, forming chlorobenzene ( C₆H₅Cl ).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
Friedel-Crafts alkylation of benzene with (CH₃)2CHCl and AlCl₃ forms C₆H₅CH(CH₃)2 (isopropylbenzene or cumene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Physical Properties - Boiling Point Dipole Moment Solubility
Friedel-Crafts alkylation with CH₃CH₂CH₂Cl and AlCl₃ in anhydrous conditions forms C₆H₅CH₂CH₂CH₃ (propylbenzene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms
In sunlight, Cl₂ adds to benzene via free radical mechanism, forming C₆H₆Cl₆ (hexachlorocyclohexane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Classification and Nomenclature and Isomerism of Haloalkanes
Moles of benzene = (39/78) = 0.5 mol . Moles of toluene = (92/92) = 1 mol . Total moles = 0.5 + 1 = 1.5 . Mole fraction = (0.5/1.5) ≈ 0.333 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor
Benzene has a planar hexagonal ring with sp2 hybridized carbons, resulting in bond angles of 120°.
Ref: NCERT Class 11 Chemistry > Chapter 9: Hydrocarbons > Topic: Aromatic Hydrocarbons - Structure of Benzene and Resonance
In benzene ( C₆H₆ ), there are 6 C-C sigma bonds, 6 C-H sigma bonds, and 3 pi bonds from alternating double bonds in its ring structure.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: VSEPR Theory and Shapes of Molecules
In C₆H₆ (benzene), there are 6 C-C sigma bonds in the ring, 6 C-H sigma bonds, totaling 12 sigma bonds (plus 3 pi bonds).
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Kossel-Lewis Approach and Octet Rule and Lewis Structures
