Practice question
Question
Which condition favors the formation of C₆H₅CH₂CH₂CH₃ from benzene and a haloalkane?
Explanation
Friedel-Crafts alkylation with CH₃CH₂CH₂Cl and AlCl₃ in anhydrous conditions forms C₆H₅CH₂CH₂CH₃ (propylbenzene).
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