Which condition favors the formation of C₆H₅CH₂CH₂CH₃ from benzene and a haloalkane?
Friedel-Crafts alkylation with CH₃CH₂CH₂Cl and AlCl₃ in anhydrous conditions forms C₆H₅CH₂CH₂CH₃ (propylbenzene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Nucleophilic Substitution Reactions - SN1 and SN2 Mechanisms