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Question

A charge of \( 11 \, \mu\text{C} \) is at the center of a cube of edge 45 cm. What is the total flux
through the cube?

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Explanation

**Closed-surface flux** depends solely on net charge inside, not external charges. This principle allows flux calculation without detailed field integration and forms cornerstone for symmetric charge distributions. Total flux: Φ = (q/ε₀) . Φ = (11 × 10⁻⁶/8.854 × 10⁻¹²) = 1.242 × 10⁶ N·m²/C . Substituting values gives 1.242 × 10⁶ N·m²/C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET and CUET.

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