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#central charge

2 public questions tagged with this topic.

A charge \( 6 \, \mu\text{C} \) is at the center of a cube of edge 20 cm. What is the total electric flux through the cu

**Electric flux** through surface measures field lines crossing it, Φ = E·A = E A cosθ for uniform field, unit N·m²/C. For circular area in xy-plane with field along z, θ = 0°, cosθ = 1, so Φ = E·πR² directly, maximum when field normal to surface. Total flux: Φ = (q/ε₀) . Φ = (6 × 10⁻⁶/8.854 × 10⁻¹²) = 6.78 × 10⁵ N·m²/C . Substituting values gives 6.78 × 10⁵ N·m²/C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Ref: NCERT > Physics Book > Electric Charges and Fields > Electric Flux

A charge of \( 11 \, \mu\text{C} \) is at the center of a cube of edge 45 cm. What is the total flux through the cube?

**Closed-surface flux** depends solely on net charge inside, not external charges. This principle allows flux calculation without detailed field integration and forms cornerstone for symmetric charge distributions. Total flux: Φ = (q/ε₀) . Φ = (11 × 10⁻⁶/8.854 × 10⁻¹²) = 1.242 × 10⁶ N·m²/C . Substituting values gives 1.242 × 10⁶ N·m²/C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET and CUET.

Ref: NCERT > Physics Book > Electric Charges and Fields > Gauss's Theorem and Total Flux