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#waves

28 public questions tagged with this topic.

PHYSICS

A particle in SHM has an amplitude of 6 cm and a frequency of 1.5 Hz . What is its maximum speed? (Take π = 3.14 )

Given: A particle in SHM has an amplitude of 6 cm and a frequency of 1.5 Hz . What is its maximum speed? (Take π = 3.14 ) These values define the system as per NCERT data. Formula: Maximum speed: v_{max = A omega. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: omega = 2π v = 2 × 3.14 × 1.5 = 9.42 rad/s . A = 0.06 m . v_{max = 0.06 × 9.42 approx 0.565 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.

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PHYSICS

The electric field of an EM wave oscillates with amplitude 48 V/m and frequency 2 × 10¹⁰ Hz . What is the amplitude

Given: The electric field of an EM wave oscillates with amplitude 48 V/m and frequency 2 × 10¹⁰ Hz . What is the amplitude of the magnetic field? (Given c = 3 × 10⁸ m/s ) These values define the system as per NCERT data. Formula: Using B_0 = E_0/c, we have B_0 = 48/3 × 10⁸= 1.6 × 10⁻⁷ T .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

A wave on a string has an amplitude of 2 cm and a wavelength of 0.5 m. What is the maximum transverse speed of a particl

Given: A wave on a string has an amplitude of 2 cm and a wavelength of 0.5 m. What is the maximum transverse speed of a particle on the string if its frequency is 20 Hz? These values define the system as per NCERT data. Formula: Amplitude a = 0.02 m, frequency v = 20 Hz. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Angular frequency: omega = 2π v = 2π × 20 = 40π rad/s . Maximum speed: v_{max = a omega = 0.02 × 40π approx 2.51 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.

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PHYSICS

A string fixed at both ends has a length of 1.4 m and a wave speed of 70 m/s. What is the frequency of its second harmon

Given: A string fixed at both ends has a length of 1.4 m and a wave speed of 70 m/s. What is the frequency of its second harmonic? These values define the system as per NCERT data. Formula: For fixed ends: v_n = n v/2L. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Second harmonic ( n = 2 ): v_2 = 2 × 70/2 × 1.4 = 140/2.8 = 50 Hz . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.

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PHYSICS

What is the frequency of light with a wavelength of 595 nm in air, given the speed of light in air is 3.0 × 10⁸m/s ?

Given: What is the frequency of light with a wavelength of 595 nm in air, given the speed of light in air is 3.0 × 10⁸m/s ? These values define the system as per NCERT data. Formula: Frequency nu = c/lambda. This is standard NCERT relation. Substitution & Calculation: lambda = 5.95 × 10⁻⁷m, c = 3.0 × 10⁸m/s . nu = frac3.0 × 10⁸⁵.95 × 10⁻⁷approx 5.04 × 10¹⁴Hz . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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PHYSICS

What is the physical basis for the formation of beats in sound waves?

Beats arise from the superposition of two waves with slightly different frequencies, causing periodic constructive and destructive interference, perceived as amplitude variation.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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PHYSICS

Which of the following is a feature of electromagnetic waves in vacuum?

Electromagnetic waves in vacuum are self-sustaining oscillations of electric and magnetic fields and do not require a material medium for propagation.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

What is the phase change when a longitudinal wave reflects off a rigid boundary?

For a longitudinal wave, a rigid boundary (fixed end) causes a compression to reflect as a compression, resulting in no phase change (0 radians), unlike transverse waves which invert.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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