Practice question
Question
A particle in SHM has an amplitude of 6 cm and a frequency of 1.5 Hz . What is its maximum speed? (Take π = 3.14 )
Explanation
Given:
A particle in SHM has an amplitude of 6 cm and a frequency of 1.5 Hz . What is its maximum speed? (Take π = 3.14 )
These values define the system as per NCERT data.
Formula:
Maximum speed: v_{max = A omega.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
omega = 2π v = 2 × 3.14 × 1.5 = 9.42 rad/s . A = 0.06 m . v_{max = 0.06 × 9.42 approx 0.565 m/s .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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