Practice question
Question
A brass wire of length 2.2 m and cross-sectional area 2 × 10â»â¶ m² is stretched by a force of 220 N . If the Young's modulus of brass is 9 × 10¹ⰠN/m², what is the stress?
Explanation
Given:
A brass wire of length 2.2 m and cross-sectional area 2 × 10â»â¶ m² is stretched by a force of 220 N . If the Young's modulus of brass is 9 × 10¹ⰠN/m², what is the stress?
These values define the system as per NCERT data.
Formula:
Stress: Stress = F/A = frac2202 × 10â»â¶= 1.1 × 10⸠N/m² ..
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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