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Practice question

Question

A brass wire of length 2.2 m and cross-sectional area 2 × 10⁻⁶ m² is stretched by a force of 220 N . If the Young's modulus of brass is 9 × 10¹⁰ N/m², what is the stress?

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Explanation

Given: A brass wire of length 2.2 m and cross-sectional area 2 × 10⁻⁶ m² is stretched by a force of 220 N . If the Young's modulus of brass is 9 × 10¹⁰ N/m², what is the stress? These values define the system as per NCERT data. Formula: Stress: Stress = F/A = frac2202 × 10⁻⁶= 1.1 × 10⁸ N/m² .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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