Practice question

Given: The electric field of an EM wave oscillates with amplitude 48 V/m and frequency 2 × 10¹⁰ Hz . What is the amplitude of the magnetic field? (Given c = 3 × 10⁸ m/s ) These values define the system as per NCERT data. Formula: Using B_0 = E_0/c, we have B_0 = 48/3 × 10⁸= 1.6 × 10⁻⁷ T .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.