#vertical velocity

Motion in a Plane and Projectile Motion

A ball is thrown at 40m/s at 30∘. What is its vertical velocity at the maximum height? (Take g\=10m/s2)

Velocity v=v₀+at. Starting from rest, v=at. With a=(ax i+ay j), magnitude |v|=t√(ax²+ay²) per NCERT vector addition. Substituting ax, ay, t gives |v| equal to 0 m/s. Hence option D is correct.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Motion in a Plane and Projectile Motion

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Motion Parameters and Calculations

A ball is thrown at 22m/s at 60∘. What is its vertical velocity at t\=1.5s? (Take g\=10m/s2,sin⁡60∘\=0.866)

Vertical velocity vy=v0sin⁡θ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations

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Motion Parameters and Calculations

A ball is thrown at 15m/s at 60∘. What is its vertical velocity after 1s? (Take g\=10m/s2,sin⁡60∘\=0.866)

Vertical velocity vy=v0sin⁡θ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations

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Straight Line Motion - Mixed Concepts

A ball is thrown at 24m/s at 37∘. What is its vertical velocity at t\=1s? (Take g\=10m/s2,sin⁡37∘\=0.6)

Vertical velocity vy=v0sin⁡θ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

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Straight Line Motion - Mixed Concepts

A ball is thrown at 30m/s at 53∘. What is its vertical velocity at t\=2s? (Take g\=10m/s2,sin⁡53∘\=0.8)

Vertical velocity vy=v0sin⁡θ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

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